1Y^2+3Y-8=Y

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Solution for 1Y^2+3Y-8=Y equation:


Simplifying
1Y2 + 3Y + -8 = Y

Reorder the terms:
-8 + 3Y + 1Y2 = Y

Solving
-8 + 3Y + 1Y2 = Y

Solving for variable 'Y'.

Reorder the terms:
-8 + 3Y + -1Y + 1Y2 = Y + -1Y

Combine like terms: 3Y + -1Y = 2Y
-8 + 2Y + 1Y2 = Y + -1Y

Combine like terms: Y + -1Y = 0
-8 + 2Y + 1Y2 = 0

Factor a trinomial.
(-4 + -1Y)(2 + -1Y) = 0

Subproblem 1

Set the factor '(-4 + -1Y)' equal to zero and attempt to solve: Simplifying -4 + -1Y = 0 Solving -4 + -1Y = 0 Move all terms containing Y to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -1Y = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -1Y = 0 + 4 -1Y = 0 + 4 Combine like terms: 0 + 4 = 4 -1Y = 4 Divide each side by '-1'. Y = -4 Simplifying Y = -4

Subproblem 2

Set the factor '(2 + -1Y)' equal to zero and attempt to solve: Simplifying 2 + -1Y = 0 Solving 2 + -1Y = 0 Move all terms containing Y to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1Y = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1Y = 0 + -2 -1Y = 0 + -2 Combine like terms: 0 + -2 = -2 -1Y = -2 Divide each side by '-1'. Y = 2 Simplifying Y = 2

Solution

Y = {-4, 2}

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